Benzoic Acid + NaOH = ?? (Neutralization Reaction)
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Benzoic acid reacts with Na2CO3 to form NaCO3 in water. It moves from the organic phase to the aqueous phase because benzoic acid is soluble in organic liquids. This allows for the separation of benzoic acid, 2,2,4-trimethylpentane, and methoxybenzene during the extraction in part l of the experiment. The reason why benzoic acid becomes soluble in water is because Na2CO3 dissociates into Na and CO3^2- ions in water, and the CO3^2- ion can act as a weak base by accepting a proton from a weak aci
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Benzoic acid + NaOH titration calculations
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Suppose you have a sample of benzoic acid dissolved in water. (a) Draw the structure of benzoic acid. (b) Now assume that aqueous NaOH is added to the benzoic acid solution until pH 12 is reached. Draw the structure of the major organic species present. (c) Finally, assume that aqueous HCl is added to the solution from (b) until pH 2 is reached. Draw the structure of the major organic species present. | Numerade
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A sample of monoprotic benzoic acid weighing 0.5823 g is dissolved in about 25 mL of water. The solution is titrated to the equivalence point using 0.1021 M NaOH . The volume of base required is 46.75 mL . Calculate the molecular weight of the solid acid. | Numerade
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