First we need to complete the square to get the coordinates of the turning point. \(y = {x^2} + 2x + 3\) \(y = {(x + 1)^2} - 1 + 3\) \(y = {(x + 1)^2} + 2\) Therefore ...
What do you think the graph of \(y = \cos 2x^\circ\) would look like? amplitude = 1, so the distance between the maximum and minimum values is 2 number of waves = 2 (period is 360Ëš ÷ 2 = 180Ëš) graph ...
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